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-15x^2+55x-30=0
a = -15; b = 55; c = -30;
Δ = b2-4ac
Δ = 552-4·(-15)·(-30)
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1225}=35$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(55)-35}{2*-15}=\frac{-90}{-30} =+3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(55)+35}{2*-15}=\frac{-20}{-30} =2/3 $
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